{"id":8466,"date":"2024-08-05T20:06:59","date_gmt":"2024-08-05T23:06:59","guid":{"rendered":"https:\/\/xequematenem.com.br\/blog\/?p=8466"},"modified":"2024-09-09T19:29:29","modified_gmt":"2024-09-09T22:29:29","slug":"questao-131-enem-ppl-2019","status":"publish","type":"post","link":"https:\/\/xequematenem.com.br\/blog\/questao-131-enem-ppl-2019\/","title":{"rendered":"Quest\u00e3o 131 \u2013 ENEM PPL 2019"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">O g\u00e1s hidrog\u00eanio \u00e9 considerado um \u00f3timo combust\u00edvel \u2014 o \u00fanico produto da combust\u00e3o desse g\u00e1s \u00e9 o vapor de \u00e1gua, como mostrado na equa\u00e7\u00e3o qu\u00edmica.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img decoding=\"async\" width=\"353\" height=\"47\" data-src=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-152.png\" alt=\"\" class=\"wp-image-8467 lazyload\" style=\"--smush-placeholder-width: 353px; --smush-placeholder-aspect-ratio: 353\/47;width:248px;height:auto\" title=\"\" data-srcset=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-152.png 353w, https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-152-300x40.png 300w\" data-sizes=\"(max-width: 353px) 100vw, 353px\" src=\"data:image\/svg+xml;base64,PHN2ZyB3aWR0aD0iMSIgaGVpZ2h0PSIxIiB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciPjwvc3ZnPg==\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Um <strong>cilindro cont\u00e9m 1 kg de hidrog\u00eanio<\/strong> e todo esse g\u00e1s foi queimado. Nessa rea\u00e7\u00e3o, s\u00e3o rompidas e formadas liga\u00e7\u00f5es qu\u00edmicas que envolvem as energias listadas no quadro.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img fetchpriority=\"high\" decoding=\"async\" width=\"483\" height=\"236\" src=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-153.png\" alt=\"\" class=\"wp-image-8468\" style=\"width:336px;height:auto\" title=\"\" srcset=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-153.png 483w, https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-153-300x147.png 300w\" sizes=\"(max-width: 483px) 100vw, 483px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Qual \u00e9 a varia\u00e7\u00e3o da entalpia, <\/strong>em quilojoule, da rea\u00e7\u00e3o <strong>de combust\u00e3o do hidrog\u00eanio contido no cilindro?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A) \u2212242 000<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">B) \u2212121 000<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">C) \u22122 500<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">D) +110 500<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E) +234 000<\/p>\n\n\n\n<p class=\"has-text-align-center has-large-font-size wp-block-paragraph\"><strong>Solu\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A varia\u00e7\u00e3o da entalpia de uma rea\u00e7\u00e3o pode ser calculada a partir das energias de liga\u00e7\u00e3o. Para isso, devemos considerar todas as liga\u00e7\u00f5es existentes entre os \u00e1tomos e tamb\u00e9m a rela\u00e7\u00e3o estequiom\u00e9trica:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" width=\"431\" height=\"56\" data-src=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-154.png\" alt=\"\" class=\"wp-image-8469 lazyload\" style=\"--smush-placeholder-width: 431px; --smush-placeholder-aspect-ratio: 431\/56;width:339px;height:auto\" title=\"\" data-srcset=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-154.png 431w, https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-154-300x39.png 300w\" data-sizes=\"(max-width: 431px) 100vw, 431px\" src=\"data:image\/svg+xml;base64,PHN2ZyB3aWR0aD0iMSIgaGVpZ2h0PSIxIiB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciPjwvc3ZnPg==\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>REAGENTES:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">As liga\u00e7\u00f5es est\u00e3o sendo rompidas. Portando, o somat\u00f3rio da energia envolvida ser\u00e1 positivo, j\u00e1 que o processo \u00e9 endot\u00e9rmico.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Pelo balanceamento, temos 2 mol de H<sub>2<\/sub> e cada mol\u00e9cula de H<sub>2<\/sub> realiza uma liga\u00e7\u00e3o H \u2013 H. Logo: <strong>2 mol x 437 kJ\/mol = 874 kJ<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Pelo balanceamento, temos 1 mol de O<sub>2<\/sub> e cada mol\u00e9cula de O<sub>2<\/sub> realiza uma liga\u00e7\u00e3o O = O. Sendo assim, temos:<strong> 1 mol x 494 kJ\/mol = 494 kJ<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Somando as energias das liga\u00e7\u00f5es dos reagentes: <strong>1368 kJ<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>PRODUTOS:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">As liga\u00e7\u00f5es est\u00e3o sendo formadas. Portando, o somat\u00f3rio da energia envolvida ser\u00e1 considerado negativo, j\u00e1 que o processo \u00e9 exot\u00e9rmico.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Pelo balanceamento, temos 2 mol de H<sub>2<\/sub>O e cada mol\u00e9cula de H<sub>2<\/sub>O realiza duas liga\u00e7\u00f5es O \u2013 H. Logo: <strong>2 mol x 2 x 463 kJ\/mol = 1852 kJ, que deve ser considerado \u2013 1852 kJ.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A varia\u00e7\u00e3o da entalpia \u00e9 dada pelo somat\u00f3rio dos valores encontrados para reagentes e produtos:<\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-2c90304e wp-block-group-is-layout-flex\">\n<p class=\"wp-block-paragraph\"><strong>\u0394H = H<sub>reagentes<\/sub> + H<sub>produtos<\/sub><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394H = 1368 kJ + (- 1852 kJ) =<strong> &#8211; 484 kJ.<\/strong><\/p>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Isso significa que para a rea\u00e7\u00e3o em quest\u00e3o, o \u0394H de combust\u00e3o \u00e9 de \u2013 484 kJ.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img decoding=\"async\" width=\"455\" height=\"39\" data-src=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-155.png\" alt=\"\" class=\"wp-image-8470 lazyload\" style=\"--smush-placeholder-width: 455px; --smush-placeholder-aspect-ratio: 455\/39;width:362px;height:auto\" title=\"\" data-srcset=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-155.png 455w, https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-155-300x26.png 300w\" data-sizes=\"(max-width: 455px) 100vw, 455px\" src=\"data:image\/svg+xml;base64,PHN2ZyB3aWR0aD0iMSIgaGVpZ2h0PSIxIiB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciPjwvc3ZnPg==\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Por fim, para calcularmos a varia\u00e7\u00e3o da entalpia de combust\u00e3o do g\u00e1s hidrog\u00eanio contido no cilindro (1 kg de H<sub>2<\/sub>), precisamos estabelecer uma simples rela\u00e7\u00e3o por regra de tr\u00eas.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">2 mol de H<sub>2<\/sub> (4 g), liberam 484 kJ de energia, 1 kg (1000 g) ir\u00e1 liberar:<\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-2c90304e wp-block-group-is-layout-flex\">\n<p class=\"wp-block-paragraph\"><strong>H<sub>2<\/sub>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;ENERGIA<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">4 g &#8212;&#8212;&#8212;&#8212;&#8212; 484 kJ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">1000 g &#8212;&#8212;&#8212;- x<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>x = 121 000 kJ<\/strong><\/p>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Alternativa B<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>O g\u00e1s hidrog\u00eanio \u00e9 considerado um \u00f3timo combust\u00edvel \u2014 o \u00fanico produto da combust\u00e3o desse g\u00e1s \u00e9 o vapor de \u00e1gua, como mostrado na equa\u00e7\u00e3o qu\u00edmica. Um cilindro cont\u00e9m 1 kg de hidrog\u00eanio e todo esse g\u00e1s foi queimado. Nessa rea\u00e7\u00e3o, s\u00e3o rompidas e formadas liga\u00e7\u00f5es qu\u00edmicas que envolvem as energias listadas no quadro. Qual [&hellip;]<\/p>\n","protected":false},"author":11,"featured_media":8468,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[87,98],"tags":[],"area-do-conhecimento":[116,120],"assunto":[],"class_list":["post-8466","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-questoes-ppl","category-2019-questoes-ppl","area-do-conhecimento-ciencias-da-natureza-e-suas-tecnologias","area-do-conhecimento-quimica"],"_links":{"self":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/8466","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/users\/11"}],"replies":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/comments?post=8466"}],"version-history":[{"count":1,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/8466\/revisions"}],"predecessor-version":[{"id":8471,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/8466\/revisions\/8471"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/media\/8468"}],"wp:attachment":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/media?parent=8466"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/categories?post=8466"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/tags?post=8466"},{"taxonomy":"area-do-conhecimento","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/area-do-conhecimento?post=8466"},{"taxonomy":"assunto","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/assunto?post=8466"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}