{"id":8686,"date":"2024-08-05T23:41:41","date_gmt":"2024-08-06T02:41:41","guid":{"rendered":"https:\/\/xequematenem.com.br\/blog\/?p=8686"},"modified":"2024-09-09T19:28:49","modified_gmt":"2024-09-09T22:28:49","slug":"questao-111-enem-ppl-2017","status":"publish","type":"post","link":"https:\/\/xequematenem.com.br\/blog\/questao-111-enem-ppl-2017\/","title":{"rendered":"Quest\u00e3o 111 \u2013 ENEM PPL 2017"},"content":{"rendered":"\n<p>Os combust\u00edveis de origem f\u00f3ssil, como o petr\u00f3leo e o g\u00e1s natural, geram um s\u00e9rio problema ambiental, devido \u00e0 libera\u00e7\u00e3o de di\u00f3xido de carbono durante o processo de combust\u00e3o. O quadro apresenta as massas molares e as <strong>rea\u00e7\u00f5es de combust\u00e3o n\u00e3o balanceadas de diferentes combust\u00edveis.<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img fetchpriority=\"high\" decoding=\"async\" width=\"886\" height=\"299\" src=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-211.png\" alt=\"\" class=\"wp-image-8687\" style=\"width:649px;height:auto\" title=\"\" srcset=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-211.png 886w, https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-211-300x101.png 300w, https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-211-768x259.png 768w\" sizes=\"(max-width: 886px) 100vw, 886px\" \/><\/figure>\n\n\n\n<p><\/p>\n\n\n\n<p>Considerando a <strong>combust\u00e3o completa de 58 g de cada um dos combust\u00edveis<\/strong> listados no quadro, <strong>a subst\u00e2ncia que emite mais CO<sub>2 <\/sub>\u00e9 o<\/strong><\/p>\n\n\n\n<p>A) etano.<\/p>\n\n\n\n<p>B) butano.<\/p>\n\n\n\n<p>C) metano.<\/p>\n\n\n\n<p>D) propano.<\/p>\n\n\n\n<p>E) acetileno.<strong><\/strong><\/p>\n\n\n\n<p class=\"has-text-align-center has-large-font-size\"><strong>Solu\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p>Como todo o carbono nos produtos de combust\u00e3o prov\u00e9m do combust\u00edvel, o coeficiente estequiom\u00e9trico do CO\u2082 na rea\u00e7\u00e3o de combust\u00e3o \u00e9 igual \u00e0 quantidade de carbono presente na f\u00f3rmula molecular de cada combust\u00edvel.<\/p>\n\n\n\n<p>Ao considerar a combust\u00e3o completa de 58 g de cada combust\u00edvel listado, e realizando as convers\u00f5es de mol para massa usando a massa molar, \u00e9 poss\u00edvel calcular a quantidade de CO\u2082 emitida por cada subst\u00e2ncia. Dessa forma, podemos determinar qual combust\u00edvel \u00e9 respons\u00e1vel pela emiss\u00e3o de maior quantidade de CO\u2082:<\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-fe9cc265 wp-block-group-is-layout-flex\">\n<p><strong>METANO:<\/strong><\/p>\n\n\n\n<p>16 g de CH<sub>4<\/sub> &#8212;&#8212;&#8211; 1 mol de CO<sub>2<\/sub><\/p>\n\n\n\n<p>58 g de CH<sub>4 <\/sub>&#8212;&#8212;&#8211; x<\/p>\n\n\n\n<p><strong>x = 3,62 mol de CO<sub>2<\/sub><\/strong><\/p>\n<\/div>\n\n\n\n<p><\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-fe9cc265 wp-block-group-is-layout-flex\">\n<p><strong>ACETILENO:<\/strong><\/p>\n\n\n\n<p>26 g de C<sub>2<\/sub>H<sub>2<\/sub> &#8212;&#8212;&#8211; 2 mol de CO<sub>2<\/sub><\/p>\n\n\n\n<p>58 g de C<sub>2<\/sub>H<sub>2 <\/sub>&#8212;&#8212;&#8211; y<\/p>\n\n\n\n<p><strong>y = 4,46 mol de CO<sub>2<\/sub><\/strong><\/p>\n<\/div>\n\n\n\n<p><\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-fe9cc265 wp-block-group-is-layout-flex\">\n<p><strong>ETANO:<\/strong><\/p>\n\n\n\n<p>30 g de C<sub>2<\/sub>H<sub>6<\/sub> &#8212;&#8212;&#8211; 2 mol de CO<sub>2<\/sub><\/p>\n\n\n\n<p>58 g de C<sub>2<\/sub>H<sub>6 <\/sub>&#8212;&#8212;&#8211; z<\/p>\n\n\n\n<p><strong>z = 3,87 mol de CO<sub>2<\/sub><\/strong><\/p>\n<\/div>\n\n\n\n<p><\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-fe9cc265 wp-block-group-is-layout-flex\">\n<p><strong>PROPANO:<\/strong><\/p>\n\n\n\n<p>44 g de C<sub>3<\/sub>H<sub>8<\/sub> &#8212;&#8212;&#8211; 3 mol de CO<sub>2<\/sub><\/p>\n\n\n\n<p>58 g de C<sub>3<\/sub>H<sub>8 <\/sub>&#8212;&#8212;&#8211; w<\/p>\n\n\n\n<p><strong>w = 3,95 mol de CO<sub>2<\/sub><\/strong><\/p>\n<\/div>\n\n\n\n<p><\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-fe9cc265 wp-block-group-is-layout-flex\">\n<p><strong>BUTANO:<\/strong><\/p>\n\n\n\n<p>58 g de C<sub>4<\/sub>H<sub>10<\/sub> &#8212;&#8212;&#8211; 4 mol de CO<sub>2<\/sub><\/p>\n\n\n\n<p>58 g de C<sub>4<\/sub>H<sub>10 <\/sub>&#8212;&#8212;&#8211; k<\/p>\n\n\n\n<p><strong>k = 4 mol de CO<sub>2<\/sub><\/strong><\/p>\n<\/div>\n\n\n\n<p><\/p>\n\n\n\n<p>Os c\u00e1lculos indicam que o acetileno \u00e9 o combust\u00edvel que gera a maior quantidade de CO\u2082 durante a combust\u00e3o para uma mesma massa.<\/p>\n\n\n\n<p><strong>Alternativa E<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Os combust\u00edveis de origem f\u00f3ssil, como o petr\u00f3leo e o g\u00e1s natural, geram um s\u00e9rio problema ambiental, devido \u00e0 libera\u00e7\u00e3o de di\u00f3xido de carbono durante o processo de combust\u00e3o. O quadro apresenta as massas molares e as rea\u00e7\u00f5es de combust\u00e3o n\u00e3o balanceadas de diferentes combust\u00edveis. Considerando a combust\u00e3o completa de 58 g de cada um [&hellip;]<\/p>\n","protected":false},"author":11,"featured_media":8687,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[87,96],"tags":[],"area-do-conhecimento":[116,120],"assunto":[],"class_list":["post-8686","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-questoes-ppl","category-2017-questoes-ppl","area-do-conhecimento-ciencias-da-natureza-e-suas-tecnologias","area-do-conhecimento-quimica"],"_links":{"self":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/8686","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/users\/11"}],"replies":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/comments?post=8686"}],"version-history":[{"count":1,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/8686\/revisions"}],"predecessor-version":[{"id":8688,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/8686\/revisions\/8688"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/media\/8687"}],"wp:attachment":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/media?parent=8686"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/categories?post=8686"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/tags?post=8686"},{"taxonomy":"area-do-conhecimento","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/area-do-conhecimento?post=8686"},{"taxonomy":"assunto","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/assunto?post=8686"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}