{"id":8770,"date":"2024-08-06T00:55:15","date_gmt":"2024-08-06T03:55:15","guid":{"rendered":"https:\/\/xequematenem.com.br\/blog\/?p=8770"},"modified":"2024-09-09T19:28:35","modified_gmt":"2024-09-09T22:28:35","slug":"questao-76-enem-2016","status":"publish","type":"post","link":"https:\/\/xequematenem.com.br\/blog\/questao-76-enem-2016\/","title":{"rendered":"Quest\u00e3o 076 \u2013 ENEM 2016"},"content":{"rendered":"\n<p>Nucle\u00f3filos <strong>(Nu<sup>\u2212<\/sup>) <\/strong>s\u00e3o <strong>bases de Lewis que reagem com haletos de alquila<\/strong>, por meio de uma rea\u00e7\u00e3o chamada <strong>substitui\u00e7\u00e3o nucleof\u00edlica<\/strong> (S<sub>N<\/sub>), como mostrado no esquema:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" width=\"766\" height=\"45\" data-src=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-238.png\" alt=\"\" class=\"wp-image-8771 lazyload\" style=\"--smush-placeholder-width: 766px; --smush-placeholder-aspect-ratio: 766\/45;width:630px;height:auto\" title=\"\" data-srcset=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-238.png 766w, https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-238-300x18.png 300w\" data-sizes=\"(max-width: 766px) 100vw, 766px\" src=\"data:image\/svg+xml;base64,PHN2ZyB3aWR0aD0iMSIgaGVpZ2h0PSIxIiB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciPjwvc3ZnPg==\" \/><\/figure>\n\n\n\n<p><\/p>\n\n\n\n<p>A rea\u00e7\u00e3o de S<sub>N<\/sub> entre <strong>met\u00f3xido de s\u00f3dio (Nu<sup>\u2212<\/sup> = CH<sub>3<\/sub>O<sup>\u2212<\/sup>) e brometo de metila fornece um composto org\u00e2nico<\/strong> pertencente \u00e0 fun\u00e7\u00e3o<\/p>\n\n\n\n<p>A) \u00e9ter.<\/p>\n\n\n\n<p>B) \u00e9ster.<\/p>\n\n\n\n<p>C) \u00e1lcool.<\/p>\n\n\n\n<p>D) haleto.<\/p>\n\n\n\n<p>E) hidrocarboneto.<\/p>\n\n\n\n<p class=\"has-text-align-center has-large-font-size\"><strong>Solu\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p>A rea\u00e7\u00e3o de substitui\u00e7\u00e3o nucleof\u00edlica (S<sub>N<\/sub>) ocorre conforme ilustrado no esquema. Quando o met\u00f3xido de s\u00f3dio (CH\u2083ONa) reage com o brometo de metila (CH\u2083Br), o \u00edon met\u00f3xido (CH\u2083O\u207b) atua como nucle\u00f3filo, resultando na seguinte rea\u00e7\u00e3o:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img decoding=\"async\" width=\"488\" height=\"62\" data-src=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-239.png\" alt=\"\" class=\"wp-image-8772 lazyload\" style=\"--smush-placeholder-width: 488px; --smush-placeholder-aspect-ratio: 488\/62;width:417px;height:auto\" title=\"\" data-srcset=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-239.png 488w, https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-239-300x38.png 300w\" data-sizes=\"(max-width: 488px) 100vw, 488px\" src=\"data:image\/svg+xml;base64,PHN2ZyB3aWR0aD0iMSIgaGVpZ2h0PSIxIiB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciPjwvc3ZnPg==\" \/><\/figure>\n\n\n\n<p>A partir disso, podemos concluir que o composto org\u00e2nico formado pertence a fun\u00e7\u00e3o \u00e9ter (oxig\u00eanio entre carbonos).<\/p>\n\n\n\n<p><strong>Alternativa A<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Nucle\u00f3filos (Nu\u2212) s\u00e3o bases de Lewis que reagem com haletos de alquila, por meio de uma rea\u00e7\u00e3o chamada substitui\u00e7\u00e3o nucleof\u00edlica (SN), como mostrado no esquema: A rea\u00e7\u00e3o de SN entre met\u00f3xido de s\u00f3dio (Nu\u2212 = CH3O\u2212) e brometo de metila fornece um composto org\u00e2nico pertencente \u00e0 fun\u00e7\u00e3o A) \u00e9ter. B) \u00e9ster. C) \u00e1lcool. D) haleto. [&hellip;]<\/p>\n","protected":false},"author":11,"featured_media":8771,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[17,23],"tags":[],"area-do-conhecimento":[116,120],"assunto":[],"class_list":["post-8770","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-questoes-do-enem","category-23","area-do-conhecimento-ciencias-da-natureza-e-suas-tecnologias","area-do-conhecimento-quimica"],"_links":{"self":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/8770","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/users\/11"}],"replies":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/comments?post=8770"}],"version-history":[{"count":1,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/8770\/revisions"}],"predecessor-version":[{"id":8773,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/8770\/revisions\/8773"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/media\/8771"}],"wp:attachment":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/media?parent=8770"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/categories?post=8770"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/tags?post=8770"},{"taxonomy":"area-do-conhecimento","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/area-do-conhecimento?post=8770"},{"taxonomy":"assunto","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/assunto?post=8770"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}