{"id":9037,"date":"2024-08-06T14:58:09","date_gmt":"2024-08-06T17:58:09","guid":{"rendered":"https:\/\/xequematenem.com.br\/blog\/?p=9037"},"modified":"2024-08-06T14:58:09","modified_gmt":"2024-08-06T17:58:09","slug":"questao-84-enem-ppl-2014-caderno-branco","status":"publish","type":"post","link":"https:\/\/xequematenem.com.br\/blog\/questao-84-enem-ppl-2014-caderno-branco\/","title":{"rendered":"Quest\u00e3o 084 \u2013 ENEM PPL 2014 (Caderno BRANCO)"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">O cobre, muito utilizado em fios da rede el\u00e9trica e com consider\u00e1vel valor de mercado, pode ser encontrado na natureza na forma de calcocita, Cu<sub>2<\/sub>S (s), de massa molar 159 g\/mol. <strong>Por meio da rea\u00e7\u00e3o Cu<sub>2<\/sub>S (s) + O<sub>2<\/sub> (g) \u2192 2 Cu (s) + SO<sub>2<\/sub> (g), \u00e9 poss\u00edvel obt\u00ea-lo na forma met\u00e1lica.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>A quantidade de mat\u00e9ria de cobre met\u00e1lico produzida a partir de uma tonelada de calcocita com 7,95% (m\/m) de pureza \u00e9<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">&nbsp;A) 1,0 \u00d7 10<sup>3<\/sup> mol.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">B) 5,0 \u00d7 10<sup>2<\/sup> mol.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">C) 1,0 \u00d7 10<sup>0<\/sup> mol.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">D) 5,0 \u00d7 10<sup>\u20131<\/sup> mol.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E) 4,0 \u00d7 10<sup>\u20133<\/sup> mol.<\/p>\n\n\n\n<p class=\"has-text-align-center has-large-font-size wp-block-paragraph\"><strong>Solu\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A pureza da calcocita \u00e9 de 7,95%. Considerando 1 tonelada (1000 kg) de calcocita, a quantidade de Cu<sub>2<\/sub>S presente \u00e9 de:<\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-2c90304e wp-block-group-is-layout-flex\">\n<p class=\"wp-block-paragraph\">100% &#8212;&#8212;&#8212;- 1000 kg de calcocita<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">7,95% &#8212;&#8212;&#8212; x (massa somente de Cu<sub>2<\/sub>S)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>x = 79,5 kg de Cu<sub>2<\/sub>S<\/strong><\/p>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">79,5 kg de Cu<sub>2<\/sub>S corresponde a massa que formar\u00e1 o cobre met\u00e1lico. Em n\u00famero de mol, 79,5 kg (79.500 g) de Cu<sub>2<\/sub>S equivalem a:<\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-2c90304e wp-block-group-is-layout-flex\">\n<p class=\"wp-block-paragraph\">159 g &#8212;&#8212;&#8212;- 1 mol de Cu<sub>2<\/sub>S<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">79.500 g &#8212;&#8212; y<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>y = 500 mol de Cu<sub>2<\/sub>S<\/strong><\/p>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">De acordo com a estequiometria da rea\u00e7\u00e3o, 1mol de Cu<sub>2<\/sub>S forma 2 mol de Cu. Considerando 500 mol de Cu<sub>2<\/sub>S, ser\u00e3o formados:<\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-2c90304e wp-block-group-is-layout-flex\">\n<p class=\"wp-block-paragraph\">1 mol de Cu2S &#8212;&#8212;&#8212;&#8212; 2 mol de Cu<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">500 mol de Cu2S &#8212;&#8212;&#8212; n<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>n = 1000 mol de Cu (1,0 x 10<sup>3<\/sup> mol)<\/strong><\/p>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Alternativa A<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>O cobre, muito utilizado em fios da rede el\u00e9trica e com consider\u00e1vel valor de mercado, pode ser encontrado na natureza na forma de calcocita, Cu2S (s), de massa molar 159 g\/mol. Por meio da rea\u00e7\u00e3o Cu2S (s) + O2 (g) \u2192 2 Cu (s) + SO2 (g), \u00e9 poss\u00edvel obt\u00ea-lo na forma met\u00e1lica. A quantidade [&hellip;]<\/p>\n","protected":false},"author":11,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[87,93],"tags":[],"area-do-conhecimento":[116,120],"assunto":[],"class_list":["post-9037","post","type-post","status-publish","format-standard","hentry","category-questoes-ppl","category-2014-questoes-ppl","area-do-conhecimento-ciencias-da-natureza-e-suas-tecnologias","area-do-conhecimento-quimica"],"_links":{"self":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/9037","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/users\/11"}],"replies":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/comments?post=9037"}],"version-history":[{"count":1,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/9037\/revisions"}],"predecessor-version":[{"id":9038,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/9037\/revisions\/9038"}],"wp:attachment":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/media?parent=9037"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/categories?post=9037"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/tags?post=9037"},{"taxonomy":"area-do-conhecimento","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/area-do-conhecimento?post=9037"},{"taxonomy":"assunto","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/assunto?post=9037"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}