{"id":9044,"date":"2024-08-06T15:07:58","date_gmt":"2024-08-06T18:07:58","guid":{"rendered":"https:\/\/xequematenem.com.br\/blog\/?p=9044"},"modified":"2024-08-06T15:08:49","modified_gmt":"2024-08-06T18:08:49","slug":"questao-88-enem-ppl-2014-caderno-branco","status":"publish","type":"post","link":"https:\/\/xequematenem.com.br\/blog\/questao-88-enem-ppl-2014-caderno-branco\/","title":{"rendered":"Quest\u00e3o 088 \u2013 ENEM PPL 2014 (Caderno BRANCO)"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">A escolha de uma determinada subst\u00e2ncia para ser utilizada como combust\u00edvel passa pela an\u00e1lise da polui\u00e7\u00e3o que ela causa ao ambiente e pela quantidade de energia liberada em sua combust\u00e3o completa. O quadro apresenta a <strong>entalpia de combust\u00e3o de algumas subst\u00e2ncias<\/strong>. As massas molares dos elementos H, C e O s\u00e3o, respectivamente, iguais a 1 g\/mol, 12 g\/mol e 16 g\/mol.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img fetchpriority=\"high\" decoding=\"async\" width=\"414\" height=\"253\" src=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-314.png\" alt=\"\" class=\"wp-image-9045\" style=\"width:347px;height:auto\" title=\"\" srcset=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-314.png 414w, https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-314-300x183.png 300w\" sizes=\"(max-width: 414px) 100vw, 414px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Levando-se em conta somente o aspecto energ\u00e9tico, <strong>a subst\u00e2ncia mais eficiente para a obten\u00e7\u00e3o de energia, na combust\u00e3o de 1 kg de combust\u00edvel, \u00e9 o<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A) etano.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">B) etanol.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">C) metanol.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">D) acetileno.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E) hidrog\u00eanio.<\/p>\n\n\n\n<p class=\"has-text-align-center has-large-font-size wp-block-paragraph\"><strong>Solu\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A subst\u00e2ncia mais eficiente para obten\u00e7\u00e3o de energia \u00e9 aquela que libera mais calor durante a combust\u00e3o. Considerando 1 kg (1000 g) como a massa de cada uma das subst\u00e2ncias, temos:<\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-2c90304e wp-block-group-is-layout-flex\">\n<p class=\"wp-block-paragraph\"><strong>Acetileno<\/strong> <strong>\u2192 26 g\/mol<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">26 g &#8212;&#8212;&#8212;&#8211; 1 298 kJ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">1000 g &#8212;&#8212;&#8211; x<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>x = 49.923 kJ de energia liberada, aproximadamente<\/strong><\/p>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-2c90304e wp-block-group-is-layout-flex\">\n<p class=\"wp-block-paragraph\"><strong>Etano \u2192 30 g\/mol<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">30 g &#8212;&#8212;&#8212;&#8211; 1 558 kJ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">1000 g &#8212;&#8212;&#8211; y<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>y = 51.933 kJ de energia liberada, aproximadamente<\/strong><\/p>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-2c90304e wp-block-group-is-layout-flex\">\n<p class=\"wp-block-paragraph\"><strong>Etanol \u2192 46 g\/mol<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">46 g &#8212;&#8212;&#8212;&#8211; 1 366 kJ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">1000 g &#8212;&#8212;&#8211; w<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>w = 29.695,65 kJ de energia liberada, aproximadamente<\/strong><\/p>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-2c90304e wp-block-group-is-layout-flex\">\n<p class=\"wp-block-paragraph\"><strong>Hidrog\u00eanio \u2192 2 g\/mol<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">2 g &#8212;&#8212;&#8212;&#8211; 242 kJ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">1000 g &#8212;&#8212;&#8211; z<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>z = 121.000 kJ de energia liberada<\/strong><\/p>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<div class=\"wp-block-group is-vertical is-layout-flex wp-container-core-group-is-layout-2c90304e wp-block-group-is-layout-flex\">\n<p class=\"wp-block-paragraph\"><strong>Metanol \u2192 32 g\/mol<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">32 g &#8212;&#8212;&#8212;&#8211; 558 kJ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">1000 g &#8212;&#8212;&#8211; k<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>k = 17.437 kJ de energia liberada, aproximadamente<\/strong><\/p>\n<\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A subst\u00e2ncia mais eficiente \u00e9 o hidrog\u00eanio.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Alternativa E<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>A escolha de uma determinada subst\u00e2ncia para ser utilizada como combust\u00edvel passa pela an\u00e1lise da polui\u00e7\u00e3o que ela causa ao ambiente e pela quantidade de energia liberada em sua combust\u00e3o completa. O quadro apresenta a entalpia de combust\u00e3o de algumas subst\u00e2ncias. As massas molares dos elementos H, C e O s\u00e3o, respectivamente, iguais a 1 [&hellip;]<\/p>\n","protected":false},"author":11,"featured_media":9045,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[87,93],"tags":[],"area-do-conhecimento":[116,120],"assunto":[],"class_list":["post-9044","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-questoes-ppl","category-2014-questoes-ppl","area-do-conhecimento-ciencias-da-natureza-e-suas-tecnologias","area-do-conhecimento-quimica"],"_links":{"self":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/9044","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/users\/11"}],"replies":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/comments?post=9044"}],"version-history":[{"count":2,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/9044\/revisions"}],"predecessor-version":[{"id":9047,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/9044\/revisions\/9047"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/media\/9045"}],"wp:attachment":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/media?parent=9044"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/categories?post=9044"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/tags?post=9044"},{"taxonomy":"area-do-conhecimento","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/area-do-conhecimento?post=9044"},{"taxonomy":"assunto","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/assunto?post=9044"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}