{"id":9095,"date":"2024-08-06T16:39:39","date_gmt":"2024-08-06T19:39:39","guid":{"rendered":"https:\/\/xequematenem.com.br\/blog\/?p=9095"},"modified":"2024-08-06T16:39:39","modified_gmt":"2024-08-06T19:39:39","slug":"questao-49-enem-ppl-2013-caderno-branco","status":"publish","type":"post","link":"https:\/\/xequematenem.com.br\/blog\/questao-49-enem-ppl-2013-caderno-branco\/","title":{"rendered":"Quest\u00e3o 049 \u2013 ENEM PPL 2013 (Caderno BRANCO)"},"content":{"rendered":"\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img fetchpriority=\"high\" decoding=\"async\" width=\"915\" height=\"400\" src=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-329.png\" alt=\"\" class=\"wp-image-9096\" style=\"width:759px;height:auto\" title=\"\" srcset=\"https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-329.png 915w, https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-329-300x131.png 300w, https:\/\/xequematenem.com.br\/blog\/wp-content\/uploads\/2024\/08\/image-329-768x336.png 768w\" sizes=\"(max-width: 915px) 100vw, 915px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">A transforma\u00e7\u00e3o qu\u00edmica em quest\u00e3o \u00e9 representada pela equa\u00e7\u00e3o:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A) CH<sub>3<\/sub>COOH (aq) + NaHCO<sub>3<\/sub> (s) \u2192 Na<sup>+<\/sup> (aq) + CH<sub>3<\/sub>COO<sup>\u2212<\/sup> (aq) + CO<sub>2<\/sub> (g) + H<sub>2<\/sub>O (l)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">B) CH<sub>3<\/sub>COOH (aq) + NaHCO<sub>3<\/sub> (s) \u2192 Na<sup>+<\/sup> (aq) + CH<sub>3<\/sub>COO<sup>\u2212<\/sup> (aq) + O<sub>2 <\/sub>(g) + H<sub>2<\/sub>O (l)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">C) CH<sub>3<\/sub>COOH (aq) + NaHCO<sub>3<\/sub> (s) \u2192 Na<sup>+<\/sup> (aq) + CH<sub>3<\/sub>COO<sup>\u2212<\/sup> (aq) + H<sub>2<\/sub>O (l)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">D) CH<sub>3<\/sub>COOH (aq) + NaHCO<sub>3<\/sub> (s) \u2192 NaCO<sup>2+<\/sup> (aq) + CH<sub>3<\/sub>COO<sup>\u2212<\/sup> (aq) + H<sub>2<\/sub>O (l)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E) CH<sub>3<\/sub>COOH (aq) + NaHCO<sub>3<\/sub> (s) \u2192 Na<sup>+ <\/sup>(aq) + CH<sub>3<\/sub>COO<sup>\u2212<\/sup> (aq) + H<sub>2<\/sub> (g) + H<sub>2<\/sub>O (l)<\/p>\n\n\n\n<p class=\"has-text-align-center has-large-font-size wp-block-paragraph\"><strong>Solu\u00e7\u00e3o<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A equa\u00e7\u00e3o qu\u00edmica que representa corretamente a rea\u00e7\u00e3o descrita \u00e9 a da op\u00e7\u00e3o A. Nessa rea\u00e7\u00e3o \u00e1cido-base, o \u00e1cido ac\u00e9tico (CH<sub>3<\/sub>COOH), presente no vinagre, reage com o bicarbonato de s\u00f3dio (NaHCO<sub>3<\/sub>\u200b) para formar o acetato de s\u00f3dio (CH<sub>3<\/sub>\u200bCOONa) e \u00e1cido carb\u00f4nico (H<sub>2<\/sub>CO<sub>3<\/sub>). Por sua vez, o \u00e1cido carb\u00f4nico formado se decomp\u00f5e rapidamente em \u00e1gua (H<sub>2<\/sub>\u200bO) e di\u00f3xido de carbono (CO<sub>2<\/sub>\u200b). O CO<sub>2<\/sub>\u200b liberado durante essa rea\u00e7\u00e3o \u00e9 o respons\u00e1vel por encher o bal\u00e3o.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Alternativa A<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>A transforma\u00e7\u00e3o qu\u00edmica em quest\u00e3o \u00e9 representada pela equa\u00e7\u00e3o: A) CH3COOH (aq) + NaHCO3 (s) \u2192 Na+ (aq) + CH3COO\u2212 (aq) + CO2 (g) + H2O (l) B) CH3COOH (aq) + NaHCO3 (s) \u2192 Na+ (aq) + CH3COO\u2212 (aq) + O2 (g) + H2O (l) C) CH3COOH (aq) + NaHCO3 (s) \u2192 Na+ (aq) + [&hellip;]<\/p>\n","protected":false},"author":11,"featured_media":9096,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[87,92],"tags":[],"area-do-conhecimento":[116,120],"assunto":[],"class_list":["post-9095","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-questoes-ppl","category-2013-questoes-ppl","area-do-conhecimento-ciencias-da-natureza-e-suas-tecnologias","area-do-conhecimento-quimica"],"_links":{"self":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/9095","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/users\/11"}],"replies":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/comments?post=9095"}],"version-history":[{"count":1,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/9095\/revisions"}],"predecessor-version":[{"id":9097,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/posts\/9095\/revisions\/9097"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/media\/9096"}],"wp:attachment":[{"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/media?parent=9095"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/categories?post=9095"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/tags?post=9095"},{"taxonomy":"area-do-conhecimento","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/area-do-conhecimento?post=9095"},{"taxonomy":"assunto","embeddable":true,"href":"https:\/\/xequematenem.com.br\/blog\/wp-json\/wp\/v2\/assunto?post=9095"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}